5n^2+27n-260=0

Solution for 5n^2+27n-260=0 equation:

5n^2+27n-260=0

a = 5; b = 27; c = -260;
Δ = b2-4ac
Δ = 272-4·5·(-260)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5929}=77$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-77}{2*5}=\frac{-104}{10}
=-10+2/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+77}{2*5}=\frac{50}{10}
=5
$